16k^2=40k

Solution for 16k^2=40k equation:

16k^2=40k

We move all terms to the left:

16k^2-(40k)=0

a = 16; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·16·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*16}=\frac{0}{32}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*16}=\frac{80}{32}
=2+1/2
$